Convert to Binary

#include
using namespace std;
#include
#include

char *entry, letter, choice[2];
int ascii, len, binary[8], total;
void prog();

int main()
{
prog();
return 0;
}

void prog()
{
entry = new char[501];
/* entry should be dynamic, otherwise a new
string entry of 501 chars would be created
each time function is called!
Talk about memory hog! */
cout<<"Enter string to convert (up to 500 chars): "; cin.getline(entry, 500); len = strlen(entry); /* get the number of characters in entry. */ /* this loop is executed for each letter in the string. */ for(int i = 0; i0) /* This while loop converts the ASCII # into binary,
stores it backwards into the binary array. */
{
/* To get the binary code one must take the decimal number in
question, take it and divide it by two repeatedly, save
the remainder (which will become the binary number), save
the whole number, divide by two, and repeat the whole
process until 0 is reached. This if-else statement serves
this functionality, by getting the remainder of the ascii
code, storing it in the array and then dividing the int
ascii by two */
if((ascii%2)==0)
{
binary[total] = 0;
ascii = ascii/2;
total++; /* increasing by one each time will yeild the
number of numbers in the array. */
}
else
{
binary[total] = 1;
ascii = ascii/2;
total++;
}
}
total--; /* due to data type factors, the program will actually
add a 0 at the end of the array that is not supposed
to be there, decrementing total will solve this
problem, as that 0 will not be displayed. */
/* this while loop displays the binary code for that letter. */
while(total>=0)
{
cout<
total--;
}
}
delete[] entry; /* free up the memory used by entry */
cout<<<"Do again(1 = yes, 2= no)?: ";
cin.getline(choice,3);
if(choice[0] == '1')
prog(); /* program is recursive, it calls itself. It's kinda
like a function loop of sorts. */
else
exit(0); /* quits the program */
}